2&K1‚¼2&K1j–2&K1z–P&K1‚µÀP&K1j–P&K1z–Š(K1‚;¿Š(K1j–Š(K1z–¨(K1‚ؽ¨(K1j–¨(K1z–>)K1‚P¾>)K1j–>)K1z–\)K1‚ ½\)K1j–\)K1z–þ,K1‚£»þ,K1j–þ,K1z–-K1‚½-K1j–-K1z–25K1‚ÿ¹25K1j–25K1z–P5K1‚½P5K1j–P5K1z–X